tan2θ if tanθ = 5
I really having a hard time understanding this.
just use your double-angle formula.
tan2θ = 2tanθ/(1-tan^2θ) = (2*5)/(1-5^2) = 10/-24 = -5/12
Thank you very much!
To find the value of tan(2θ) given that tan(θ) = 5, we can use the double angle formula for tangent. The formula states that tan(2θ) = 2tan(θ) / (1 - tan^2(θ)).
In this case, substitute the value given: tan(θ) = 5.
tan(2θ) = 2 * 5 / (1 - 5^2).
Using the formula, simplify the expression:
tan(2θ) = 10 / (1 - 25).
Now, simplify the denominator:
tan(2θ) = 10 / (-24).
Finally, simplify the fraction:
tan(2θ) = -5/12.
Therefore, if tan(θ) = 5, then tan(2θ) = -5/12.