A heat transfer of 9.0*105J is required convert a block of ice at 20C to water at 15C. What was the mass of the block of ice?
is this missing a minus someplace?
_20
To find the mass of the block of ice, we need to use the specific heat capacity and the heat of fusion of water.
The specific heat capacity of ice is 2.09 J/g·°C, and the heat of fusion for ice is 334 J/g.
First, we need to calculate the heat required to raise the temperature of ice from -20°C to 0°C:
Q1 = (mass1) × (specific heat capacity of ice) × (change in temperature)
Q1 = (mass1) × (2.09 J/g·°C) × (20°C)
Next, we calculate the heat required to convert the ice at 0°C to water at 0°C:
Q2 = (mass1) × (heat of fusion of ice)
Finally, we calculate the heat required to raise the temperature of the water from 0°C to 15°C:
Q3 = (mass2) × (specific heat capacity of water) × (change in temperature)
Q3 = (mass2) × (4.18 J/g·°C) × (15°C)
The total heat transfer is the sum of Q1, Q2, and Q3:
Total heat transfer = Q1 + Q2 + Q3 = 9.0 × 10^5 J
Since we are looking for the mass of the block of ice, which means we need to find the values of mass1 and mass2. We can rewrite the equation as:
Total heat transfer = (mass1) × (2.09 J/g·°C) × (20°C) + (mass1) × (334 J/g) + (mass2) × (4.18 J/g·°C) × (15°C)
Now we can substitute the values and solve for the mass of the block of ice.