A conductor has a diameter of 1.00mm and length 2.00m.if the resistance of the material is 0.1 ohms,it's resistivity is

A.3.93 ×10^-6
B.2.55 ×10^2
C.3.93 ×10^-8
D.2.25×10^2?

resistance = resistivity * length/area

0.1 = res * 2/ (pi *.0005*.0005)
.05 * pi * 25*10^-8
125 pi * 10^-10
1.25 pi *10*-8
C

To find the resistivity of the conductor, we can use the formula:

Resistance (R) = Resistivity (ρ) * (Length (L) / Area (A))

Given:
Diameter of the conductor = 1.00 mm
Radius (r) of the conductor = diameter / 2 = 1.00 mm / 2 = 0.50 mm = 0.50 × 10^-3 m
Length (L) = 2.00 m
Resistance (R) = 0.1 Ω

To find the area (A) of the conductor, we can use the formula for the area of a circle:

Area (A) = π * (Radius (r))^2

Substituting the given values:

Area (A) = π * (0.50 × 10^-3 m)^2

Now we can substitute the values for resistance (R), length (L), and area (A) into the formula to solve for resistivity (ρ):

0.1 Ω = ρ * (2.00 m / (π * (0.50 × 10^-3 m)^2))

Rearranging the formula to solve for resistivity (ρ):

ρ = (0.1 Ω) / (2.00 m / (π * (0.50 × 10^-3 m)^2))

Calculating this expression gives:

ρ = (0.1 Ω) / (2.00 m / (3.1416 * (0.50 × 10^-3 m)^2))

ρ = (0.1 Ω) / (2.00 / (3.1416 * 0.50 × 10^-3 m^2))

ρ = (0.1 Ω) / (2.00 / (3.1416 * 0.25 × 10^-6 m^2))

ρ = (0.1 Ω) / (2.00 / 7.854 × 10^-6 m^2)

ρ = (0.1 Ω) / (2.00 × 7.854 × 10^-6 m^2)

ρ = 0.1 Ω / 1.571 × 10^-5 m^2

Therefore, the resistivity of the material is approximately 6.36 × 10^-6 Ω.m.

Looking at the answer choices, none of them match the calculated value. It's possible that there might be an error in the question or the answer choices provided.