The pressure in a car tire is 35psi on a winter day when the temperature is 0 degrees Celsius. What is the pressure in the same car tire, assuming the volume of the tire has not changed, on a summer day when the temperature is 30 degrees Celsius? (Use gay-lussac’s law)
You are not answering the question-Stop giving those calculations. Why can’t you guys give a simple straightforward answer. If the temperature outside is 70F at 35 psi, when the temperature drops to 30F it is ok to at 1 to 2 psi and when the temperature raises back to 70F check your tires pressure again and adjust to 35 psi. It that simple.
See this answer posted by Bob Pursley a day or so ago.
https://www.jiskha.com/questions/1798529/Please-help-me-I-dont-understand-The-pressure-in-a-car-is-35psi-on-a-winter
To find the pressure in the car tire on a summer day, we can use Gay-Lussac's Law, which states that the pressure and temperature of a gas are directly proportional if the volume is constant.
According to Gay-Lussac's Law, we can use the following formula:
(P1 / T1) = (P2 / T2)
Where:
P1 = Initial pressure
T1 = Initial temperature
P2 = Final pressure (what we want to find)
T2 = Final temperature
Given:
P1 = 35 psi
T1 = 0 degrees Celsius
T2 = 30 degrees Celsius
First, we need to convert the temperatures to Kelvin since Gay-Lussac's Law requires temperature in Kelvin.
To convert Celsius to Kelvin, we use the formula:
T(K) = T(°C) + 273.15
Converting the temperatures:
T1 = 0 + 273.15 = 273.15 K
T2 = 30 + 273.15 = 303.15 K
Now, we can plug in the values into the formula:
(P1 / T1) = (P2 / T2)
(35 / 273.15) = (P2 / 303.15)
To find P2, we can solve for P2 by cross-multiplying and rearranging the equation:
35 * 303.15 = P2 * 273.15
10615.25 = P2 * 273.15
Now, divide both sides of the equation by 273.15 to solve for P2:
P2 = 10615.25 / 273.15
P2 ≈ 38.853 psi
Therefore, the pressure in the car tire on a summer day when the temperature is 30 degrees Celsius would be approximately 38.853 psi.