calculate the molecular mass of sulphur if 35.5g sulphur dissolves in 1 00 g of CS2 to produce a solution that has boiling point of 49.48c
I assume you have the normal boiling point of CS2 as well as the Kb for CS2 but didn't post them..
dT = Kb*molality
dT = 49.48 - normal point CS2 = ?
You know Kb (look that up) and Tb(normal boiling point). Solve for molality.
Then molality = m = mols S/kg solvent. You know m and kg solvent, solve for molS
Then mols S = grams S/molar mass S. YOu have mols and grams, solve for molar mass.
Post your work if you get stuck.