show the products of the reaction of CH3CH2CH=CH2 with (a) HCL (b) Br2 (c) H2
student in grad 10th
I NEED THE ANSWERS
(a) The reaction of CH3CH2CH=CH2 with HCl would undergo an addition reaction, resulting in the formation of chloroethane (CH3CH2CH2Cl).
Step 1: The pi bond in the alkene breaks, and a new bond forms between the carbon atom and the hydrogen atom from HCl.
CH3CH2CH=CH2 + HCl → CH3CH2CH2Cl
(b) The reaction of CH3CH2CH=CH2 with Br2 would undergo an addition reaction as well, resulting in the formation of 1,2-dibromoethane (CH3CHBrCH2Br).
Step 1: The pi bond in the alkene breaks, and a new bond forms between the carbon atom and each of the bromine atoms from Br2.
CH3CH2CH=CH2 + Br2 → CH3CHBrCH2Br
(c) The reaction of CH3CH2CH=CH2 with H2 would undergo a hydrogenation reaction, resulting in the formation of propane (CH3CH2CH3).
Step 1: The pi bond in the alkene breaks, and two new bonds form between the carbon atoms and two hydrogen atoms from H2.
CH3CH2CH=CH2 + H2 → CH3CH2CH3
To determine the products of the reaction of CH3CH2CH=CH2 with different reagents, we need to consider the type of reaction that is likely to occur.
(a) Reaction with HCl:
The addition of HCl to an alkene typically involves a reaction called electrophilic addition. In this reaction, the pi bond of the alkene is broken, and the hydrogen and chloride atoms are added to the carbon atoms of the double bond. This results in the formation of a chloride-substituted alkane.
The reaction can be represented as follows:
CH3CH2CH=CH2 + HCl -> CH3CH2CH(Cl)-CH3
(b) Reaction with Br2:
The reaction of an alkene with bromine usually involves a type of reaction known as electrophilic addition as well. In this case, the pi bond of the alkene is broken, and the bromine atoms are added to the carbon atoms of the double bond, resulting in the formation of a vicinal dibromide.
The reaction can be represented as follows:
CH3CH2CH=CH2 + Br2 -> CH3CH2CH(Br)-CH2Br
(c) Reaction with H2:
The reaction of an alkene with hydrogen gas, H2, is called hydrogenation and typically involves the addition of hydrogen across the pi bond. It is a reduction reaction that forms an alkane.
The reaction can be represented as follows:
CH3CH2CH=CH2 + H2 -> CH3CH2CH2CH3
Please note that these reactions are based on general trends, and the conditions and reaction conditions might be adjusted to obtain specific products. Additionally, it is advisable to consult experimental data or specific reaction mechanisms for a more accurate understanding of the reactions.