How much will $8500 be worth if it is invested for 10 years at 6.5%/a, compounded weekly?

8500 * [1 + (.065 / 52)]^(10 * 52)

P = Po(1+r)^n.

r = 0.065/52 = 0.0049 = Weekly % rate expressed as a decimal.
n = 10yrs. * 52comp./yr. = 520 Compounding periods.

P = 8500*(1.0049)^520 =

To calculate the future value of an investment with compound interest, we can use the formula:

FV = P * (1 + r/n)^(n*t)

Where:
FV = Future Value
P = Principal Amount (initial investment)
r = Annual Interest Rate (in decimal form)
n = Number of times interest is compounded per year
t = Number of years

In this case:
P = $8500
r = 6.5% = 0.065 (decimal form)
n = 52 (compounded weekly)
t = 10 years

Now we can plug in the values into the formula and solve for FV:

FV = $8500 * (1 + 0.065/52)^(52*10)

Calculating this value will give us the future value of the investment after 10 years.

To find out how much $8500 will be worth after 10 years of investing at a 6.5% annual interest rate, compounded weekly, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A = the future value of the investment
P = the principal amount (initial investment)
r = the annual interest rate (in decimal form)
n = the number of times interest is compounded per year
t = the number of years

In this case, the principal amount (P) is $8500, the annual interest rate (r) is 6.5% or 0.065 in decimal form, the number of times interest is compounded (n) is 52 (weekly), and the number of years (t) is 10.

Substituting the values into the formula:

A = $8500(1 + 0.065/52)^(52*10)

Let's calculate it:

A = $8500(1 + 0.00125)^(520)

To calculate this expression, we can use a calculator or a spreadsheet. The result of this calculation will give us the future value (A) of the investment after 10 years.