A 60 kilogram tourist tries horseback riding in tagaytay.The horse has a mass of 500 kilogram.He moves around a circular path with a radius of 10 meter at a rate of 5 meter per second.Compute the centripetal force.
mv2/r=force
F=60×(5raised to the 2nd power)/10=150n
To compute the centripetal force acting on the horse, we need to use the formula:
Fc = (m * v^2) / r
where Fc is the centripetal force, m is the mass of the tourist + horse system, v is the velocity of the horse, and r is the radius of the circular path.
In this case, the mass (m) is the sum of the mass of the tourist and the horse, which is:
m = mass of tourist + mass of horse
= 60 kg + 500 kg
= 560 kg
The velocity (v) of the horse is given as 5 meters per second.
The radius (r) of the circular path is given as 10 meters.
Now we can substitute the values into the formula:
Fc = (560 kg * (5 m/s)^2) / 10 m
= (560 kg * 25 m^2/s^2) / 10 m
= 14,000 kg*m/s^2
= 14,000 N
Therefore, the centripetal force acting on the horse is 14,000 Newtons.
centripetal force on the horse?
m v^2 /r=force
force= 60*(5^2)/10= 6*25=126N