The amount of oxalic acid (equ.wt.63) required to prepare 500ml of its 0.10 N solution is
Here is a very useful formula.
mL x N x mew = grams.
mL = millileters
N = normality
mew = milliequivalent weight
500 mL x 0.10 N x 0.063 = grams.
Solve for grams.
To calculate the amount of oxalic acid required to prepare a 0.10 N solution in 500 ml, you need to know the molar concentration of the solution and the molecular weight of oxalic acid.
First, let's determine the number of moles of oxalic acid required for a 0.10 N solution. N stands for normality, which represents the number of equivalents of a substance per liter of solution.
Normality (N) = (number of equivalents) / (volume in liters)
In this case, the normality (N) is 0.10 N, and the volume is 500 ml, which is equal to 0.5 liters.
0.10 N = (number of equivalents) / 0.5 L
Rearranging the equation, we get:
(number of equivalents) = 0.10 N * 0.5 L
Next, we need to determine the molecular weight of oxalic acid, which is provided as 63 g/mol.
Now, we can calculate the amount of oxalic acid in grams using the following formula:
Amount (in grams) = (number of moles) * (molecular weight)
To find the number of moles, we need to calculate it by dividing the number of equivalents by the equivalent weight of oxalic acid.
Equivalent weight = molecular weight / number of equivalents
Since oxalic acid has two acidic functional groups, its equivalent weight is half its molecular weight.
Equivalent weight = 63 g/mol / 2 = 31.5 g/equivalent
Finally, we can calculate the amount of oxalic acid in grams:
Amount (in grams) = (0.10 N * 0.5 L) * 31.5 g/equivalent
Simplifying the equation further:
Amount (in grams) = 0.05 * 31.5 g
Therefore, the amount of oxalic acid required to prepare a 0.10 N solution in 500 ml is 1.575 grams.