an airline flies two different planes over the same route. THe faster of the two plans travels at 540 miles per hour, and the toher plane tralves at 450 miles per hour. How many more can the faster plane travel in 12 seconds than the slower plane?
(Im sorry I have another question)
Eleven seconds after a deep sea diver jumps into the ocean he is 69 feet below sea level and 28 seconds later, he is 195 feet below sea level. If he is descending nder water at a constant rate, how many feet below sea level will he be 1.5 min after his initial descent?
just convert the speed difference (90 mi/hr) to mi/s by dividing by 3600 (the number of seconds in an hour)
his dive rate is (195-69)/28 = 9/2 ft/s
So, how many seconds more does he dive? Multiply that by 3/2 and addit to the 195 ft down where is is now.
Or, you can devise the general depth equation using your two points:
(11,-69) and (39,-195)
using the two-point form for a line.
and then plug in 90 seconds
To find out how many more miles the faster plane can travel in 12 seconds than the slower plane, we need to calculate the distance covered by each plane in that time period.
First, let's convert 12 seconds to hours by dividing it by 3600 (the number of seconds in an hour):
12 seconds / 3600 seconds/hour = 0.00333 hours
For the faster plane:
Distance = Speed * Time
Distance = 540 miles/hour * 0.00333 hours
Distance = 1.8 miles
For the slower plane:
Distance = Speed * Time
Distance = 450 miles/hour * 0.00333 hours
Distance = 1.5 miles
To find the difference in distance traveled between the two planes in 12 seconds, subtract the distance covered by the slower plane from the distance covered by the faster plane:
1.8 miles - 1.5 miles = 0.3 miles
Therefore, the faster plane can travel 0.3 miles more than the slower plane in 12 seconds.
Now let's move on to the second question:
If the deep sea diver descends 69 feet below sea level in 11 seconds and then descends 195 feet below sea level in a total of 28 seconds, we can find the average rate of descent per second.
Rate of descent = Change in depth / Change in time
For the first 11 seconds:
Rate of descent = 69 feet / 11 seconds = 6.27 feet/second
For the next 17 seconds:
Rate of descent = (195 feet - 69 feet) / 17 seconds = 7.65 feet/second
Since the diver descends at a constant rate, we can assume the average rate of descent over this time period is 6.27 feet/second + 7.65 feet/second divided by 2 = 6.96 feet/second.
To find out how many feet below sea level the diver will be 1.5 minutes (90 seconds) after the initial descent, we multiply the average rate of descent by the time:
Depth = Rate of descent * Time
Depth = 6.96 feet/second * 90 seconds
Depth = 626.4 feet
Therefore, 1.5 minutes (90 seconds) after the initial descent, the deep sea diver will be 626.4 feet below sea level.