Jennifer went to the post office for stamps. She bought the same number of 8 cents stamps and 10 cents stamps. She also bought as many 2 cents stamps as both of the other two combined. How many of each kind did she get if she paid a total of $4.40 for them all?
(8 * n) + (10 * n) + (2 * 2 n) = 440
solve for n
To solve this problem, we can use algebraic equations to represent the given information.
Let's assume that Jennifer bought 'x' 8 cents stamps, 'x' 10 cents stamps, and 'x + x' (2x) 2 cents stamps.
The total cost of the 8 cents stamps would be 8x cents.
The total cost of the 10 cents stamps would be 10x cents.
The total cost of the 2 cents stamps would be 2(2x) = 4x cents.
According to the information provided, Jennifer paid a total of $4.40, which equates to 440 cents.
So, we can form the equation:
8x + 10x + 4x = 440
Combining like terms:
22x = 440
Dividing both sides of the equation by 22:
x = 20
Now that we know the value of 'x', we can find the number of each type of stamp.
Number of 8 cents stamps = x = 20
Number of 10 cents stamps = x = 20
Number of 2 cents stamps = 2x = 2 * 20 = 40
Therefore, Jennifer bought 20 of each type of stamp: 20 of the 8 cents stamps, 20 of the 10 cents stamps, and 40 of the 2 cents stamps.