A conductor of length 5m carrying a current of 15A is placed in a uniform magnetic field of flux density 0 25T. If the conductor is placed at 60° to the field then the force on it is?
The answer i got is 10
To calculate the force on a conductor placed in a magnetic field, you can use the formula:
Force (F) = I * L * B * sin(θ)
Where:
- F is the force on the conductor
- I is the current flowing through the conductor (in amperes)
- L is the length of the conductor (in meters)
- B is the magnetic field flux density (in Tesla)
- θ is the angle between the conductor and the magnetic field (in degrees)
Given:
- Current (I) = 15A
- Length (L) = 5m
- Magnetic field (B) = 0.25T
- Angle (θ) = 60°
Let's plug these values into the formula:
F = 15A * 5m * 0.25T * sin(60°)
To calculate the value of sin(60°), you can use a scientific calculator or reference a trigonometric table. In this case, sin(60°) equals √3 / 2 ≈ 0.866.
F = 15A * 5m * 0.25T * 0.866
Now, perform the multiplication:
F ≈ 10 Newtons
Therefore, the force on the conductor is approximately 10 Newtons.