Physics

A machine gun fires a bullet with an initial velocity of 200m/s at an angle of 60° to the horizontal. If g=10m/s2, the total time of flight of the bullet is?

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  1. Vo = 200m/s[60o],
    Yo = 200*sin60 = 173.2 m/s. = Ver. component of initial velocity.

    Y = Yo + g*Tr = 0,
    173.2 + (-10)Tr = 0,
    Tr = 17.3 s. = Rise time.

    Tf = Tr = 17.3 s. = Fall time.

    Tr + Tf = Time in flight.

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    posted by henry2,

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