A copper strip 20cm wide and 1.5mm thick is placed in a magnetic field of 1.75wbm^2.if a current of 220A is set up in the strip,what hall potential difference appears across the strip?(n=8.5×10^28m^2 and e=1.6×10^-19)?
Yes
To find the Hall potential difference across the copper strip, we need to use the formula:
Hall Voltage (VH) = (B * I * d) / (n * e)
where:
- B is the magnetic field strength in Tesla (T),
- I is the current flowing through the strip in Amperes (A),
- d is the thickness of the strip in meters (m),
- n is the charge carrier density in inverse square meters (m^-2),
- e is the elementary charge in Coulombs (C).
First, let's convert the given dimensions into SI units:
Width of the strip (w) = 20 cm = 0.2 m
Thickness of the strip (d) = 1.5 mm = 0.0015 m
Now we can substitute the values into the formula:
VH = (B * I * d) / (n * e)
The magnetic field strength (B) is given as 1.75 wbm^2. However, we need to convert it to Tesla (T) by dividing by 10000:
B = 1.75 wbm^2 / 10000 = 0.000175 T
Next, substitute the values we have:
VH = (0.000175 T * 220 A * 0.0015 m) / (8.5 × 10^28 m^-2 * 1.6 × 10^-19 C)
Now, calculate the Hall potential difference:
VH = (0.00004095) / (13.6)
≈ 0.003011 V
Therefore, the Hall potential difference across the copper strip is approximately 0.003011 V or 3.011 mV.