Rita and sita start jogging at the same point but in opposite directions. If the rate of one jogger is 2 mph faster than the other. After 3 hours, they are 30 miles apart, what is the rate of the faster jogger?
[r + (r - 2)] * 3 = 30
solve for r
1st jogger: X mi/h.
2nd jogger: (x+2) mi/h.
d2 - d1 = 30 miles.
3(x+2) - (-3x) = 30,
3x+6 + 3x = 30,
X = ?
x+2 = __mi/h. = speed of 2nd jogger.
To solve this problem, we need to set up equations based on the given information.
Let's assume that the rate of the slower jogger is x mph. Since the rate of the faster jogger is 2 mph faster, the rate of the faster jogger would be (x + 2) mph.
Now, we know that distance = speed x time. Since both joggers started from the same point, the sum of their distances traveled will be equal to the total distance covered, which is 30 miles.
The distance traveled by the slower jogger in 3 hours is 3x miles.
The distance traveled by the faster jogger in 3 hours is 3(x + 2) miles.
So, our equation becomes:
3x + 3(x + 2) = 30
Simplifying this equation:
3x + 3x + 6 = 30
6x + 6 = 30
6x = 30 - 6
6x = 24
x = 24/6
x = 4
Therefore, the rate of the slower jogger is 4 mph. And the rate of the faster jogger is 4 + 2 = 6 mph.
Hence, the rate of the faster jogger is 6 mph.