A truck pulls a trailer at 75km/h and exerts a uniform pulling force of 800N on the trailer .calculate
1. The work done by the trailer in 30min.
2.the power required to pull the trailer.
75000 meters / 3600 seconds = 20.8 meters/second
2. power = force * speed = 20.8 * 800 Joules/second or Watts
1. work = power *time = that power * 30*60 seconds
easier to do 2 before 1 because do not have to calculate distance
A block stone having a mass of 75kg is hauled along a horizontal floor for a distance of 100m in 2min. The coefficient of friction is 0.3. Calculate horizontal force required
1. Well, if the truck is pulling the trailer for 30 minutes, that's quite a workout! To calculate the work done by the trailer, we can use the formula:
Work = Force x Distance
In this case, the force is 800N, but we need to find the distance. Since the truck is traveling at 75km/h, we need to convert that to meters per minute. So:
Distance = Speed x Time
= (75 km/h) x (30 min) x (1000 m/1 km) x (1 h/60 min)
Now we can plug these values into the formula and calculate the work done by the trailer:
Work = 800N x Distance
2. To calculate the power required to pull the trailer, we can use the formula:
Power = Work / Time
Since we already calculated the work done by the trailer, we can divide that by the time, which is 30 minutes. But don't forget to convert it to seconds first:
Time = 30 min x 60 s/min
Now we can plug these values into the formula and calculate the power required to pull the trailer:
Power = Work / Time
Oh sorry, I forgot I'm a Clown Bot and numbers are not really my thing. But hey, did you hear about the truck and the trailer that went to a comedy show? They were hauling laughs!
To calculate the work done by the trailer and the power required to pull it, we will use the following equations:
1. Work (W) = Force (F) x Distance (d) x cos(theta)
2. Power (P) = Work (W) / time (t)
1. The work done by the trailer in 30 minutes (0.5 hours):
First, let's convert the given speed from km/h to m/s:
75 km/h = 75,000 m/60 min = 1,250 m/min = 20.83 m/s
The work done can be calculated using the formula:
W = F x d x cos(theta)
Since the pulling force is uniform, the angle (theta) between the force and displacement is zero degrees, and cos(0) is equal to 1.
W = 800 N x 20.83 m/s x 0.5 hours
To convert the time from hours to seconds, we multiply by 60:
t = 0.5 hours x 60 min/hour x 60 s/min = 1,800 s
W = 800 N x 20.83 m/s x 1,800 s = 29,989,440 J
Therefore, the work done by the trailer in 30 minutes is 29,989,440 Joules.
2. The power required to pull the trailer:
The power can be calculated using the formula:
P = W / t
Substituting the values:
P = 29,989,440 J / 1,800 s
P ≈ 16,661.36 W
Therefore, the power required to pull the trailer is approximately 16,661.36 Watts.
To calculate the work done by the trailer in 30 minutes, we can use the formula:
Work = Force x Distance
However, we need to find the distance traveled by the trailer in 30 minutes. We can do this by converting the truck's speed from km/h to m/s and then multiplying it by the time.
1. Calculate the distance traveled by the trailer in 30 minutes:
Convert the speed from km/h to m/s:
75 km/h * (1000 m/1 km) * (1 h/3600 s) = 20.83 m/s
Now multiply the speed by the time:
Distance = 20.83 m/s * 30 min * (60 s/1 min) = 37,500 meters
2. Calculate the work done by the trailer:
Work = Force (800 N) * Distance (37,500 meters) = 30,000,000 Joules
Therefore, the work done by the trailer in 30 minutes is 30,000,000 Joules.
To calculate the power required to pull the trailer, we can use the formula:
Power = Work / Time
In this case, we can use the work we calculated in part 1, but we need to convert the time from minutes to seconds.
2. Calculate the power required to pull the trailer:
Time = 30 min * (60 s/1 min) = 1800 seconds
Power = Work (30,000,000 Joules) / Time (1800 seconds) = 16,667 Watts
Therefore, the power required to pull the trailer is 16,667 Watts.