A blacksmith dropped a 1.5kg iron bead at 300c into some quantity of water. If the temperature of the water from 15c to 18c, what is the mass of water assuming no heat is lost to the surrounding?(Take the specific heat of iron as 0.46jkg-1 and that of water as 4.2*103jkg-1).

To find the mass of water, we can use the concept of heat transfer in the equation:

Q = mcΔT

Where:
Q is the heat transfer (in joules)
m is the mass (in kilograms)
c is the specific heat capacity (in joules per kilogram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)

In this case, we have the following information:

Mass of the iron bead, m_iron = 1.5 kg
Specific heat capacity of iron, c_iron = 0.46 J/kg°C
Initial temperature of the water, T_initial_water = 15°C
Final temperature of the water, T_final_water = 18°C

To calculate the heat transfer from the iron bead to the water, we need to determine the heat gained by the water:

Q_water = mc_waterΔT_water

Now, we can substitute the given values:

Q_water = m_water * (4.2 * 10^3 J/kg°C) * (18°C - 15°C)

To find the mass of water, we need the heat transfer value (Q_water). To determine Q_water, we also need the mass of the iron bead (m_iron) and the specific heat capacity of the iron (c_iron). Unfortunately, we don't have enough information to calculate the mass of water without additional data.