please help me to calculate this question how many grams of FeCl3 will be obtained when you 20g of Fe react with Class?
38.056g
58.04g
To calculate the grams of FeCl3 obtained when 20g of Fe reacts with Cl2, you need to determine the stoichiometry of the reaction. The balanced equation for the reaction between Fe and Cl2 is:
2Fe + 3Cl2 → 2FeCl3
This equation tells us that for every 2 moles of Fe, we need 3 moles of Cl2 to produce 2 moles of FeCl3.
Now, let's calculate the molar mass of FeCl3:
Fe: atomic mass = 55.85 g/mol
Cl: atomic mass = 35.45 g/mol
FeCl3: (1 Fe × 55.85 g/mol) + (3 Cl × 35.45 g/mol) = 162.2 g/mol
Since the molar mass of FeCl3 is 162.2 g/mol, we can now calculate the number of moles of FeCl3 using the given mass of Fe.
First, convert the mass of Fe to moles:
20g Fe × (1 mol Fe / 55.85 g Fe) = 0.358 mol Fe
According to the stoichiometry of the balanced equation, 2 moles of Fe react to form 2 moles of FeCl3. Therefore, the number of moles of FeCl3 formed will also be 0.358 mol.
Finally, calculate the mass of FeCl3 using the molar mass:
0.358 mol FeCl3 × (162.2 g FeCl3 / 1 mol FeCl3) = 58 g FeCl3
So, when 20g of Fe reacts with Cl2, you will obtain approximately 58 grams of FeCl3.
0.2
Class? Class? You mean Chlorine?
If your reaction is
2Fe + 3Cl2 = 2FeCl3
then you see that each mole of Fe produces one mole of FeCl3.
So, how many moles of Fe are in 20g?
How many grams in that many moles of FeCl3?