Use a balance chemical equation to explain the behaviour of tetraoxosulphate(vi)acid when it reacts with magnesiumtrioxocarbonate(iv)?
To explain the behavior of tetraoxosulfate(VI) acid (H2SO4) when it reacts with magnesiumtrioxocarbonate(IV) (MgCO3), we need to write a balanced chemical equation for the reaction.
First, let's break down the reactants and products:
Tetraoxosulfate(VI) acid: H2SO4
Magnesiumtrioxocarbonate(IV): MgCO3
The reaction will produce magnesium sulfate (MgSO4), carbon dioxide (CO2), and water (H2O).
Now, let's write the balanced chemical equation:
H2SO4 + MgCO3 → MgSO4 + CO2 + H2O
To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
First, let's balance the sulfate (SO4) ion:
H2SO4 + MgCO3 → MgSO4 + CO2 + H2O
Next, balance the magnesium (Mg) atom:
H2SO4 + MgCO3 → MgSO4 + CO2 + H2O
Finally, balance the hydrogen (H) and oxygen (O) atoms:
H2SO4 + MgCO3 → MgSO4 + CO2 + H2O
Now, the equation is balanced, and it shows the reaction between tetraoxosulfate(VI) acid and magnesiumtrioxocarbonate(IV).