1000w heater is used in the determination of specific latent heat of vaporization of water and it took 4 minutes for 500g of water to be changed to steam. calculate the latent heat of vaporization of water.
a watt is a joule per second
find total joules input , divide by mass of water
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To calculate the latent heat of vaporization of water, we can use the equation:
Q = mL
Where:
Q is the heat energy released or absorbed
m is the mass of the substance
L is the specific latent heat of vaporization
In this case, we have a 1000W heater, which means it releases 1000 Joules of energy per second. Since the experiment took 4 minutes (or 240 seconds), the total energy provided by the heater would be:
Total Energy (Q) = Power x Time = 1000W x 240s = 240000 Joules
Next, we need to find the amount of water converted to steam. Given that 500g of water was changed to steam, the mass (m) would be 500g.
Finally, we can substitute the values into the equation to solve for the specific latent heat of vaporization (L):
240000 Joules = 500g x L
To find L, we can rearrange the equation as follows:
L = (240000 Joules) / (500g)
L ≈ 480 J/g
Therefore, the specific latent heat of vaporization of water is approximately 480 J/g.