Four groups of students spun the same two-color spinner with the outcomes shown in the table. Which percentage is most likely to be the portion of the spinner painted green?
Group 1: Green| 32|Blue|18
Group 2: Green|5|Blue|4
Group 3: Green|66|Blue|44
Group 4: Green|31|Blue|24
I think its 64% but idk Help!!
generally, the larger the sample, the more reliable the outcome.
66/110 = 60%
To determine which percentage is most likely to be the portion of the spinner painted green, we need to analyze the given outcomes from each group.
In Group 1, out of a total of 50 spins (32 green + 18 blue), the proportion of green spins is 32/50 = 0.64 or 64%.
In Group 2, out of a total of 9 spins (5 green + 4 blue), the proportion of green spins is 5/9 = 0.5555 or 55.55% (rounded to two decimal places).
In Group 3, out of a total of 110 spins (66 green + 44 blue), the proportion of green spins is 66/110 = 0.6 or 60%.
In Group 4, out of a total of 55 spins (31 green + 24 blue), the proportion of green spins is 31/55 = 0.5636 or 56.36% (rounded to two decimal places).
From the given outcomes, the percentages of the spinner painted green are 64%, 55.55%, 60%, and 56.36%. Among these options, the highest percentage is 64%. Therefore, the most likely percentage representing the portion of the spinner painted green is 64%.