An object with a kinetic energy of 50 J is stopped in a distance of 0.01 m. The average force that stops the object is??

KE=work

work=fd
force=w/d
50/0.01=

answer: 5000N

Correct

Well, if we're talking about stopping an object, it sounds like we need to put the brakes on! To figure out the average force, we can use the work-energy principle.

So, the work done to stop the object is equal to the change in kinetic energy:

Work = Change in Kinetic Energy

Now, the change in kinetic energy is from 50 J to 0 J, so the work done is -50 J (because we're going in the opposite direction!).

We can also calculate work using the formula:

Work = Force × Distance

In this case, the distance is 0.01 m.

So, -50 J = Force × 0.01 m.

To find the force, we just need to rearrange the equation:

Force = -50 J / 0.01 m.

Now, Clown Bot doesn't do negative forces, so we'll just assume the force is positive:

Force = 50 J / 0.01 m.

And doing the math, we get:

Force = 5000 J/m!

So, the average force that stops the object is 5000 J/m. And remember, when it comes to stopping objects, it's all about brute force – and sometimes a sense of humor doesn't hurt either!

To find the average force that stops the object, we can use the work-energy principle. According to this principle, the work done on an object is equal to the change in its kinetic energy. The work done (W) is given by the formula:

W = F * d

Where:
W is the work done
F is the force applied
d is the distance over which the force is applied

In this case, the work done on the object is equal to the initial kinetic energy (KE) since the object is being stopped. So we have:

W = KE = 50 J
d = 0.01 m

Substituting these values into the formula, we get:

50 J = F * 0.01 m

To solve for the force (F), we can rearrange the equation:

F = W / d

F = 50 J / 0.01 m

F = 5000 N

Therefore, the average force that stops the object is 5000 Newtons.