in the hare's apparatus water rises to a height of 26.5cm in one limb.if a liquid rises to a height of 20.4cm in the other limb .what is the relative density of the liquid?
p = rho = density
p1*26.5 = p1*20.4
the density ratio is the inverse of the height ratio
I think the Dr meant ... p1 * 26.5 = p2 * 20.41
To be honest about it I don't know what I meant. Two ratios are possible and I didn't know which the student wanted.
From the web site https://physicsmax.com/to-compare-the-densities-of-two-liquids-by-means-of-hares-apparatus-6248
p1h1 = p2h2
Then I interpret the problem as p1*26.5 = p2*20.4. The problem says the height is 26.5 "in one limb". The height is 20.5 in the "other limb". "one limb" and "the other limb" doesn't do much to tell me which is h1 and which is h2. So the ratio is 26.5/20.4 or 20.4/26.5 depending upon how we interpret one limb and the other limb. Perhaps I shouldn't have answered the question since I couldn't interpret it properly. But I'm a sucker at trying to help. :-)
To find the relative density of the liquid, we can use the formula:
Relative Density = h₁ / h₂
Where:
h₁ = height of the liquid in one limb (20.4 cm)
h₂ = height of water in the other limb (26.5 cm)
Therefore, the relative density of the liquid is:
Relative Density = 20.4 cm / 26.5 cm
Simplifying the calculation:
Relative Density ≈ 0.77
So, the relative density of the liquid is approximately 0.77.