A 600.0 kg roller coaster is going around vertical loop with a radius of 10.0 meters. The speed of the coaster is 14m/s at the top of the loop.
What it the magnitude of the CENTRIPETAL force on the roller coaster, to the nearest whole number of newtons?
Fc=mv^2/r
600.0kg(14)^2/10.0=
Answer: 11760 N
Am I correct?
looks good
are significant figures an issue?
You are correct! The formula for centripetal force is Fc = mv^2/r, where m represents the mass of the object, v represents the velocity, and r represents the radius of the loop.
Plugging in the given values:
m = 600.0 kg,
v = 14 m/s,
r = 10.0 m,
we can calculate the centripetal force:
Fc = (600.0 kg) * (14 m/s)^2 / (10.0 m) = 11760 N.
Therefore, the magnitude of the centripetal force on the roller coaster is 11760 N (to the nearest whole number of newtons).