Hey can I have some help here?
My question:
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form.
Answers so far: None
Can someone help me :(
P(2)=1/6
P(not 2)=5/6
I cannot help you nay farther.
HOPE THIS HELPS!
Your wrong Lily almost everybody gives answers on Jiskha.
@lily calm donw jeez
Of course! I'd be happy to help you with that.
To find the probability of rolling an even number and then not rolling a 2 on a number cube, we need to determine the number of favorable outcomes and total outcomes.
Step 1: Determine the Total Outcomes
A number cube has 6 sides, numbered 1 through 6. When rolled, it can land on any of these numbers. So, the total number of outcomes is 6.
Step 2: Determine the Favorable Outcomes
To find the probability of rolling an even number, we need to determine how many even numbers are on the number cube. In this case, the even numbers are 2, 4, and 6. So, there are 3 favorable outcomes for the first roll.
For the second roll, we need to find the number of outcomes that are not a 2. Since we roll the number cube twice and we cannot have a 2 on the second roll, there are 5 possible outcomes (1, 3, 4, 5, and 6), and only 4 of them are even.
Step 3: Calculate the Probability
To find the probability, we divide the number of favorable outcomes by the total number of outcomes:
P(even, then not 2) = (number of favorable outcomes) / (total number of outcomes)
P(even, then not 2) = (3/6) * (4/5)
Simplifying this expression gives us:
P(even, then not 2) = 2/5
So, the probability of rolling an even number and then not rolling a 2 is 2/5.
Thanx Anonymous! XD
YOU ARE SO IN TROUBLE! This is a site to help not cheat. Your soposed to help them not give the answers!
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