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a simple pendulum has a period of 4.2sec. when the pendulum is shortened by 1 m the period is 3.7s. what is the acceleration of
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T = 2 pi sqrt(L/g) 4.2/(2 pi) = sqrt (L/g) 3.7/(2 pi) = sqrt ( (L-1)/g ) L/g = .447 (L-1)/g = .347 =
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The period (the time required for one complete swing) of a simple pendulum varies directly as the square root of its length. If
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Since the second pendulum is 1/4 as long as the first pendulum, the period will be sqrt(1/4) or 1/2
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A simple pendulum consists of a ball connected to one end of a thin brass wire. The period of the pendulum is 2.0000 s. The
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. The period of the heated pendulum is 2.0014 s.
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A simple pendulum consists of a ball connected to one end of a thin brass wire. The period of the pendulum is 2.15 s. The
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T=2πsqrt(L/g) => L=T²g/4π²= =2.15²•9.8/4•π²=1.1475 m L₁=L+ΔL = L+αLΔt= =1.1475 +
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A simple pendulum consists of a ball connected to one end of a thin brass wire. The period of the pendulum is 1.45 s. The
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assuming you have zero calculus. period=2PI sqrt (l/g) solve for original length l. now, change in
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A simple pendulum is 9.00 m long.
(a) What is the period of simple harmonic motion for this pendulum if it is hanging in an
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If it is accelerating upward at that rate, the effective value g is g' = g + a = 11.8 m/s^2 instead
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A simple pendulum has a 2.5 kg mass attached to a string that is 0.65 m in length. If the pendulum is released at an angle of
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To find the period of a simple pendulum, we can use the formula: T = 2π * √(L/g) Where: T =
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A simple pendulum of massA simple pendulum of mass 50kg oscillates with an amplitude of 4cm and period of 2s . Determine the
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Please check for typos. To get angular velocity you need length of the rod.
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The simple pendulum in a tall clock is 0.30 m long.
What is the period of this pendulum? T = s What is the frequency of this
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Your course materials should have included the equation for the period: T = 2 pi * sqrt(L/g) In your
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a simple pendulum has a period of 4.2 s. when it is shortened by 1.0 m the period is only 3.7 s.
A. without assuming a value for
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T =2 pi sqrt(L/g) = k sqrt L where k is a constant (on earth) k sqrt L = 4.2 k sqt (L-1) = 3.7 k^2 L
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