if a string has a stiffness of 950nm,what work will be done in extending the spring by 60cm
Stiffness in nm?
To calculate the work done in extending a spring, you can use Hooke's Law equation.
Hooke's Law states that the force required to extend or compress a spring by a certain distance is directly proportional to that distance. The equation is given by: F = k * x
Where:
- F is the force applied to the spring
- k is the spring constant (stiffness) of the spring
- x is the distance the spring is extended or compressed
Given that the string has a stiffness of 950 N/m (newtons per meter), and the spring is extended by 60 cm (0.6 meters), we can calculate the work done as follows:
First, we need to calculate the force applied to the spring using Hooke's Law equation: F = k * x
F = 950 N/m * 0.6 m
F = 570 N
Next, we can calculate the work done using the formula: W = F * d
Where:
- W is the work done
- F is the force applied to the spring
- d is the distance over which the force is applied
In this case, the distance (d) is the same as the extension of the spring, which is 0.6 meters.
W = 570 N * 0.6 m
W = 342 J (joules)
Therefore, the work done in extending the spring by 60 cm is 342 joules.