A water balloon with a mass of 1.20 kg is falling from a roof. If the average force of friction is 0.500 N, what is the acceleration on the balloon in m/s2?
I am not sure how to get started
1.20kg x 9.80 m/s^2= 11.76-0.500=11.26
11.26=1.20a
a=9.38 m/s^2??
looks good to me
Yes, but not sure I would say it that way
Fdown = m a down
mg - .5 = ma
a = (mg -.5)/m = (1.2*9.8 - .5) / 1.2 = 11.26/1.2 = 9.38 down
To find the acceleration of the water balloon, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
The net force acting on the water balloon can be calculated by subtracting the force of friction from the gravitational force. The force of friction opposes the motion and acts in the opposite direction, while the gravitational force acts downward.
Let's break down the steps:
1. Calculate the gravitational force:
The gravitational force acting on the water balloon is equal to the product of its mass and the acceleration due to gravity (9.8 m/s^2). In this case, the gravitational force will be:
Gravitational force = mass * acceleration due to gravity
2. Calculate the net force:
The net force is the vector sum of all the forces acting on the object. In this case, the force of friction is opposing the motion, so it will act in the opposite direction. The net force can be calculated as:
Net force = Gravitational force - Force of friction
3. Calculate the acceleration:
Now that you have the net force, you can use Newton's second law to find the acceleration. The formula is:
Net force = mass * acceleration
You can rearrange the formula to solve for acceleration:
acceleration = Net force / mass
4. Plug in the values and calculate:
Substitute the known values into the equation and solve for acceleration:
acceleration = (Net force) / mass
By following these steps and plugging in the given values (1.20 kg for the mass and 0.500 N for the force of friction), you can calculate the acceleration of the water balloon in m/s^2.