An illustration revealing a process of puzzle-solving. It shows various numbers scattered in a haphazard, disordered manner, signifying the chaotic arrangement of the professor's phone digits. It's important that all numbers from one to nine are included. The image also includes symbols of common number operations (minus, plus, greater than, less than, equals, odds and evens symbols) denoting the conditions given for the arrangement of these numbers. The image should not contain any text.

A Professor in havard University, Sent His Phone Number In A Disorderly Manner To His Brilliant Students. The Disordered Phone Number Was 64001128454.

To Know His Real Phone Number, He Gave The Students The Following Conditions;
1. Eight (8) Must Comes In Between Two Zeroes (0's).
2. The First Number After The First Condition Is Met Must Not Be An Odd Number And It Must Be Greater Than 5.
3. The Seventh Number Must Be 1.
4. The Fifth And Sixth Number Must Be Two Numbers Whose Difference Is 1 And The Bigger Number Must Comes First.
5. The Fifth And Sixth Numbers Are Greater Than 2.
6. The Ninth And Tenth Numbers Are The Same.
7. The Eighth Number Is Greater Than The Last Number.
8. The Phone Number Must Be Eleven Digits.
What Was The Professor's Real Phone
Number?
i need to understand the arithemtic way to these answer

see the answer 08065412441

but i need the steo

08065121441

Interesting, start with an observation.

To have 11 digits, we must have a 1 at the start, (for long distance?)
Since the area code of Harvard and most of Massachusetts is 617, and there is no 7 in his scrambled number ...... ?????
anyhow .....

we must see 080 as a block of numbers by #1
#2, we could have a block of 0806, 0808 , but there is only one 8 and I used it, so it must be 0806
#3 we must have 1 xxx xx1 xxxx
possibilities so far:

1 x08 061 xxxx
1 080 6x1 xxxx , not possible, no area code starts with 0
1 xx0 806 1xxx, not possible, 1 not in 7th place, violates #3
1 xxx xx1 0806

numbers left over: 42454
For #4, the only two numbers left with a difference of 1 are 4 and 5
with 5 in 5th and 4 in 6th position
so we are down to 1 xxx 541 0806

Sofar all conditions including #5 are met , we have 4,2,4 left
Can't meet any of the remaining conditions!

Check over my logic, I can't see any error in it

If that is the answer, it is an invalid phone number, as I stated in my

first part of the reply.

All phone numbers in the US and Canada have a 3 digit area code
followed by 7 numbers for a total of 10 digits.
If you call long distance, usually you have to put a 1 in front, but it is
usually not written. Since Harvard is in Mass, you answer is not a valid
phone number.
e.g. one phone number for Harvard:
Harvard University Public Affairs & Communications
Tel: (617) 495-1585

08065412441

08075412454

To find the professor's real phone number based on the given conditions, we can break it down step by step and analyze each condition:

Condition 1: Eight (8) must come in between two zeroes (0's).
Looking at the given number, "64001128454," we can see that the first condition is already satisfied since there are two zeroes (0's) with an eight (8) in between.

Condition 2: The first number after the first condition is met must not be an odd number, and it must be greater than 5.
After satisfying the first condition, we find that the first number after the two zeroes (0's) and eight (8) is 4. Since 4 is an even number and not greater than 5, this condition is not satisfied.

Condition 3: The seventh number must be 1.
Looking at the given number, the seventh number is 2, which does not fulfill this condition.

Since conditions 2 and 3 are not met, the given number "64001128454" cannot be the professor's real phone number.

Please note that without further information or additional conditions, it is not possible to determine the professor's real phone number.