35.8 of a mixture of potassium trioxochlorate (v) were heated to a constant mass. if the residual weighed 24.5 what was the percentage mass of the potassium chloride in the mixture (k=39 (l= 3,5,6=16)kcl is not decomposed on heating
solve the calculation
38.5 what? grams, tons, pounds. ?
A mixture of what? I am assuming it is a mixture of 38.5 g KClO3 and KCl and the question is how much KCl is in the mixture initially.
To solve this calculation, we will use the concept of stoichiometry.
First, let's calculate the initial mass of the mixture. We know that 35.8% of the mixture is potassium trioxochlorate (KClO3). Therefore, the initial mass of KClO3 can be calculated as follows:
Initial mass of KClO3 = Percentage mass of KClO3 in the mixture * Total mass of the mixture
= 35.8% * Total mass of the mixture
Next, let's calculate the mass of potassium chloride (KCl) in the mixture. Since KClO3 decomposes to form KCl, any residual mass after heating will be due to potassium chloride only. Therefore, the mass of KCl can be calculated as:
Mass of KCl = Total mass after heating - Initial mass of KClO3
= 24.5 g - Initial mass of KClO3
Finally, let's calculate the percentage mass of KCl in the mixture. This can be calculated as:
Percentage mass of KCl = (Mass of KCl / Total mass of the mixture) * 100
Now, let's substitute the given values into the equations:
Initial mass of KClO3 = 35.8% * Total mass of the mixture
= 0.358 * Total mass of the mixture
Mass of KCl = 24.5 g - (0.358 * Total mass of the mixture)
Percentage mass of KCl = (Mass of KCl / Total mass of the mixture) * 100
Using these equations, we can solve for the percentage mass of KCl in the mixture.
To solve this calculation, we need to understand the chemical reaction taking place and use stoichiometry to find the percentage mass of potassium chloride in the mixture.
Given:
Mass of the mixture of potassium trioxochlorate (KClO3) = 35.8 g
Mass of the residual = 24.5 g
The chemical equation for the decomposition of potassium trioxochlorate is:
2 KClO3(s) --> 2 KCl(s) + 3 O2(g)
From the equation, we can see that 2 moles of KClO3 will yield 2 moles of KCl. This means the molar ratio of KClO3 to KCl is 2:2 or 1:1.
First, we need to find the moles of KClO3 present in the mixture.
Molar mass of KClO3 = (1 x 39.1) + (3 x 16) + (16 + 3 x 35.5) = 122.55 g/mol
Moles of KClO3 = mass of KClO3 / molar mass of KClO3
= 35.8 g / 122.55 g/mol
Next, we need to find the moles of KCl produced.
Since the moles of KClO3 and KCl are in a 1:1 ratio, the moles of KCl will be the same as the moles of KClO3.
Now, we can find the mass of KCl using the moles of KCl and its molar mass.
Molar mass of KCl = 39.1 g/mol
Mass of KCl = moles of KCl x molar mass of KCl
Finally, we can calculate the percentage mass of KCl in the original mixture.
Percentage mass of KCl in the mixture = (mass of KCl / mass of mixture) x 100
By substituting the values obtained in the calculations, you should be able to find the percentage mass of KCl in the mixture.