A uniform rectangular marble slab is 3.4m and 2.0m wide.it has a mass of 180kg.its originally lying on surface flat ground. How much work is needed to stand it on It's short end? pls with formula need
The center of mass is also the center of the rectangle.
To stand it on a short end, the center of mass must thus be lifted 1.7m
Now just apply the usual formula for work, which I'm sure you have:
work = weight * distance
To calculate the work needed to stand the uniform rectangular marble slab on its short end, we will use the formula:
Work = Force × Distance
First, let's calculate the force required. The force required to stand the slab on its short end is equal to its weight. Weight can be calculated using the formula:
Weight = mass × gravity
Given that the mass of the slab is 180 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the weight as follows:
Weight = 180 kg × 9.8 m/s^2
Next, we need to find the distance over which the force is applied. In this case, since the slab is being stood on its short end, the distance is the height of the slab. The height of the slab can be determined from its dimensions, which is 3.4 m.
Now, we can calculate the work using the formula:
Work = Weight × Height
Substituting the values we obtained:
Work = (180 kg × 9.8 m/s^2) × 3.4 m
Calculating this further gives:
Work = 5,292 N × 3.4 m
Work ≈ 17,992.8 Joules
Therefore, approximately 17,992.8 Joules of work is needed to stand the uniform rectangular marble slab on its short end.