h(x) = (√(x+12) - 3)/(x + 3)
it is continuous for x > -12, as long as x ≠ -3
find h(-3)
a. -1/9
b. -1/6
c. 1/9
d. 1/6
multiply top and bottom by (√(x+12) + 3) and the 0/0 is no longer a problem
h(-3) is still undefined, but you will get the limit correctly