if three sides of a triangle are 6cm ,8cm and 10cm then find the altitude of the triangle using the largest side as base....
really need help with this question
Did you notice that 6^2 + 8^2 = 10^2, so you have a right-angled triangle.
Sketch that triangle ABC, so that AB=8 , BC=6 and AC = 10
draw the altitude BD, where D is on AC
label angles A and C as x and y. Yous should notice that you have
3 similar triangles and we can use ratios to find BD
Using ABC and BDC
BD/8 = 6/10
BD = 48/10 = 4.8
Well, I'm a clown bot, so I'm here to bring in the fun! Let's solve this triangle puzzle together.
To find the altitude of a triangle, we can use the formula:
Altitude = (2 * Area of Triangle) / Base
Now, the area of a triangle can be found using Heron's formula:
Area = sqrt(s * (s - a) * (s - b) * (s - c))
Where s = (a + b + c) / 2
Since the sides of the triangle are 6cm, 8cm, and 10cm, let's plug these values into the formulas.
First, let's find the semi-perimeter (s):
s = (6 + 8 + 10) / 2 = 12
Now, let's find the area using Heron's formula:
Area = sqrt(12 * (12 - 6) * (12 - 8) * (12 - 10))
Area = sqrt(12 * 6 * 4 * 2)
Area = sqrt(576)
Area = 24
Using the formula for altitude, substituting in the values:
Altitude = (2 * 24) / 10
Altitude = 48 / 10
Altitude = 4.8 cm
So, the altitude of the triangle using the largest side as the base is approximately 4.8cm.
Hope that helps, and remember to always have fun with math - it's a circus of numbers after all!
To find the altitude of a triangle, we can use the formula:
Altitude = (2 * Area) / Base
First, let's find the area of the triangle using Heron's formula:
s = (a + b + c) / 2 [where a, b, and c are the lengths of the sides]
s = (6 + 8 + 10) / 2
s = 24 / 2
s = 12
Area = √(s * (s - a) * (s - b) * (s - c))
Area = √(12 * (12 - 6) * (12 - 8) * (12 - 10))
Area = √(12 * 6 * 4 * 2)
Area = √(576)
Area = 24
Now that we have the area, we can find the altitude:
Altitude = (2 * Area) / Base
Altitude = (2 * 24) / 10
Altitude = 48 / 10
Altitude = 4.8 cm
Therefore, the altitude of the triangle using the largest side as the base is 4.8 cm.
To find the altitude of a triangle, we can use the formula:
Area = (base * altitude) / 2
Here, the base of the triangle is the longest side, which is 10cm. We need to find the altitude.
First, let's calculate the area of the triangle using Heron's formula:
s = (a + b + c) / 2
where s is the semi-perimeter and a, b, and c are the lengths of the sides of the triangle.
In this case, a = 6cm, b = 8cm, and c = 10cm.
s = (6 + 8 + 10) / 2
s = 12
Now, let's calculate the area of the triangle:
Area = √(s * (s - a) * (s - b) * (s - c))
Area = √(12 * (12 - 6) * (12 - 8) * (12 - 10))
Area = √(12 * 6 * 4 * 2)
Area = √(576)
Area = 24 cm²
Now that we have the area, we can substitute it into the formula for area:
Area = (base * altitude) / 2
24 = (10 * altitude) / 2
Let's solve for altitude:
24 = 5 * altitude
altitude = 24 / 5
altitude = 4.8 cm
Therefore, the altitude of the triangle using the largest side as the base is 4.8 cm.