Which masses of HNO3 nitric acid and water should be mixed to prepare 1000 grams of UAM 8% solution in mass of HNO3?
8% of 1000 g is 80 g ... HNO3
the rest is water
To find the masses of nitric acid (HNO3) and water needed to prepare a 1000-gram solution with 8% nitric acid, you need to use the concept of mass percent.
Let's assume the mass of HNO3 in the final solution is "m" grams. Since the solution is 8% nitric acid, the remaining mass (1000 - m) grams would be water.
The 8% nitric acid solution implies that the mass of HNO3 would be 8% of the total solution mass (m) and the mass of water would be 92% of the total solution mass (1000 - m).
You can set up the following equation to solve for "m":
(m / 1000) * 100 = 8
Simplifying the equation:
m = (8 * 1000) / 100
m = 80 grams
Therefore, 80 grams of nitric acid (HNO3) should be mixed with (1000 - 80) grams of water to prepare a 1000-gram solution with 8% nitric acid.