Find the sum of a geometric series with the following values: a1=3; r=2; n=10
i got;
2,880
That's not what I get. How did you do it?
Sn = a(r^n-1)/(r-1)
To find the sum of a geometric series, you can use the formula:
Sn = a1 * (1 - r^n) / (1 - r)
In this formula:
- Sn refers to the sum of the series
- a1 is the first term of the series
- r is the common ratio of the series
- n is the number of terms in the series
Let's substitute the given values into the formula:
a1 = 3
r = 2
n = 10
Sn = 3 * (1 - 2^10) / (1 - 2)
Now, let's simplify and calculate the expression:
Sn = 3 * (1 - 1024) / (-1)
Sn = 3 * (-1023) / (-1)
Sn = -3069
Therefore, the sum of the geometric series with a1=3, r=2, and n=10 is -3069.