How many moles of each ion are present, per liter, in a solution that is labeled “0.221 M
CaCl2 ”? CaCl2 Ca +2 + 2 Cl-
.221M means .221 moles/liter
So, look at the molecular formulas to see how many moles of each component there are. It will be a multiple of .221
Well, let's calculate it with a touch of humor, shall we?
Since we know the molarity of CaCl2 is 0.221 M, we can assume that it contains 0.221 moles of CaCl2 per liter.
Now, for every molecule of CaCl2, we get one Ca2+ ion and two Cl- ions. So, for every mole of CaCl2, we also get one mole of Ca2+ ions and two moles of Cl- ions.
Therefore, in a 0.221 M solution of CaCl2, you would find 0.221 moles per liter of Ca2+ ions and double that, which is 0.442 moles per liter of Cl- ions.
So, in conclusion, there are 0.221 moles/L of Ca2+ ions and 0.442 moles/L of Cl- ions in the solution. That's quite a party of ions, don't you think?
To find the number of moles of each ion per liter in a solution of "0.221 M CaCl2," we need to first understand that the concentration given is for the entire compound, CaCl2. This means that the concentration of calcium ions (Ca+2) and chloride ions (Cl-) would be twice that of the compound concentration since the compound dissociates into one calcium ion and two chloride ions.
Step 1: Convert the compound concentration to moles per liter.
The compound concentration is given as 0.221 M. This means that there are 0.221 moles of CaCl2 per liter of the solution.
Step 2: Find the moles per liter of each ion.
Since CaCl2 dissociates into one Ca+2 ion and two Cl- ions, the moles of Ca+2 would be equal to the moles of CaCl2, while the moles of Cl- ions would be twice the moles of CaCl2.
Therefore, the number of moles of each ion per liter in the solution "0.221 M CaCl2" would be:
- Ca+2 ions: 0.221 moles per liter
- Cl- ions: 2 * 0.221 moles per liter
So, the solution contains 0.221 moles of Ca+2 ions and 2 * 0.221 moles of Cl- ions per liter.
To determine the number of moles of each ion present per liter in a solution of CaCl2, you will need to refer to the given molarity of 0.221 M.
1. Start by breaking down the formula CaCl2 into its component ions: Ca+2 and 2 Cl-.
2. The molarity of CaCl2 refers to the concentration of the entire compound. So, the concentration of Ca+2 and Cl- will be half of the given molarity for CaCl2 since you have two Cl- ions for every Ca+2 ion.
3. Calculate the moles of each ion by multiplying the molarity by the volume of the solution in liters. Since we're interested in moles per liter, the volume can be considered 1 liter.
4. For Ca+2: Multiply the molarity of CaCl2 by 1 to get the number of moles per liter.
Moles of Ca+2 = 0.221 M * 1 L = 0.221 moles/L
5. For Cl-, multiply the molarity of CaCl2 by 2 to account for the two Cl- ions in each molecule.
Moles of Cl- = (0.221 M * 2) * 1 L = 0.442 moles/L
So, in a solution labeled "0.221 M CaCl2", you would have 0.221 moles of Ca+2 and 0.442 moles of Cl- per liter.