From a committee of 6 girls and 4 boys, a name is selected. Then another name is selected. What is the probability that both people drawn will be girls?
2/15
9/25
3/5
1/3
i believe 9/25 but im not sure...
6/10 * 5/9 = 1/3
thx u
To determine the probability of selecting two girls in consecutive draws from a committee of 6 girls and 4 boys, we need to calculate the probability of the first draw being a girl and then the second draw also being a girl.
Step 1: Probability of selecting a girl in the first draw:
There are 6 girls out of 10 total members in the committee. Therefore, the probability of selecting a girl in the first draw is 6/10 or 3/5.
Step 2: Probability of selecting a girl in the second draw:
After the first draw, there are now 5 girls and 9 remaining members. So, the probability of selecting a girl in the second draw is 5/9.
Step 3: Probability of both draws being girls:
To calculate the probability of two independent events occurring together, we multiply the probabilities of each event. So, the probability of both draws being girls is (3/5) * (5/9), which simplifies to 1/3.
Therefore, the correct answer is 1/3.
To solve this problem, we need to calculate the probability of selecting a girl from the committee twice in a row.
First, let's find the probability of selecting a girl for the first name.
The committee has a total of 6 girls and 4 boys, so the probability of selecting a girl for the first name is 6/10 or 3/5.
After the first name is selected, there are now 5 girls left out of 9 people (since one name has already been selected). So, the probability of selecting a girl for the second name is 5/9.
To find the probability of both people being girls, we multiply the probabilities of each event happening independently:
P(both girls) = P(first girl) * P(second girl)
P(both girls) = (3/5) * (5/9)
Simplifying, we get:
P(both girls) = 15/45 or 1/3
Therefore, the correct answer is 1/3.