A car moving at 22.0 m/s accelerates at 3.00 m/s2 for 2.39 seconds. What will the final speed be in m/s?
do I use v subf= at+v sub0
3.00x2.39 +22.0= answer 29.17??
v = Vi + at
so yes right
22 + 3 * 2.39 = 22 + 7.17 = 29.17 yes agree
To find the final speed of a car, you can use the formula:
v[sub]f[/sub] = v[sub]0[/sub] + at
where:
v[sub]f[/sub] is the final speed,
v[sub]0[/sub] is the initial speed,
a is the acceleration, and
t is the time.
In this case, the values given are:
v[sub]0[/sub] = 22.0 m/s (initial speed),
a = 3.00 m/s² (acceleration), and
t = 2.39 seconds (time).
Substituting these values into the formula:
v[sub]f[/sub] = 22.0 m/s + (3.00 m/s²)(2.39 s)
v[sub]f[/sub] = 22.0 m/s + 7.17 m/s
v[sub]f[/sub] = 29.17 m/s
So, the final speed will be 29.17 m/s.