WHAT IS THE BOND LINE FORMULAE FOR 4-BROMOPENT-1-ENE

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4-bromopent-1-ene

To determine the bond-line formula for 4-bromopent-1-ene, you need to know the structural formula of the molecule.

Here's how you can obtain the bond-line formula:

1. Start by writing the molecular formula for 4-bromopent-1-ene, which is C5H9Br. This formula tells you that the molecule is composed of 5 carbon atoms, 9 hydrogen atoms, and 1 bromine atom.

2. Identify the position of the bromine atom in the carbon chain. In this case, the bromine atom is attached to the fourth carbon atom (counting from one end of the chain).

3. Determine the double bond position. Since it is called pent-1-ene, it means that the double bond is between the first and second carbon atoms.

4. To represent the molecule in bond-line formula, start by writing the carbon skeleton in a straight line. In this case, it's a pentagon shape representing the 5 carbon atoms.

5. Next, add the hydrogen atoms to the carbons. Each carbon atom should have the appropriate number of hydrogen atoms attached. Carbon atoms should have 4 bonds in total, including any attached substituents (like bromine or double bonds).

6. Identify and place the bromine atom as a substituent on the appropriate carbon atom. In this case, it will be on the fourth carbon atom.

7. Finally, indicate the double bond between the first and second carbon atoms using a double line.

The bond-line formula for 4-bromopent-1-ene should look like this:

H H H Br
| | | |
H - C - C = C - C - C - H
| |
H H

This representation shows the carbon backbone as a straight line, with substituents (hydrogen and bromine atoms) attached to the appropriate carbon atoms. The double bond is shown as a double line between the first and second carbon atoms.