at what height above the ground must a body of mass 10kg be situated in order to have potential energy equal in value to the kinetic energy possessed by another body of mass 10kg moving with a velocity of 10m/s
PE = mgh
KE = 1/2 mv^2
so, set them equal and solve for h
Great
A body of mass 3kg is raised 4m above the ground.calculate the potential energy if g=10/s²
To find the height above the ground, where a body of mass 10 kg must be situated to have potential energy equal to the kinetic energy possessed by another body of mass 10 kg moving with a velocity of 10 m/s, we need to understand the formulas for potential energy and kinetic energy.
The potential energy (PE) of an object in a gravitational field can be calculated using the formula:
PE = m * g * h
Where:
PE = potential energy
m = mass of the object
g = acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
h = height above the ground
The kinetic energy (KE) of an object can be calculated using the formula:
KE = (1/2) * m * v^2
Where:
KE = kinetic energy
m = mass of the object
v = velocity of the object
Since we are looking for the height above the ground at which the potential energy is equal to the kinetic energy, we can set up an equation as follows:
PE = KE
m * g * h = (1/2) * m * v^2
Now we can solve the equation:
10 kg * 9.8 m/s^2 * h = (1/2) * 10 kg * (10 m/s)^2
Simplifying:
98 h = (1/2) * 10 * 100
98 h = 500
h = 500 / 98
h ≈ 5.10 meters
Therefore, the body of mass 10 kg must be situated approximately 5.10 meters above the ground to have potential energy equal to the kinetic energy possessed by another body of mass 10 kg moving with a velocity of 10 m/s.