What.work.is.done.when.a.force.of.20N.moves.a.load.5M.in.its.direction
W = F*d = 20 * 5 =
To determine the work done when a force of 20N moves a load 5m in its direction, you can use the formula for work:
Work = Force × Distance × Cosine(theta)
Where:
- Force is the magnitude of the force applied (20N)
- Distance is the magnitude of the displacement (5m)
- Cosine(theta) represents the angle between the force and the direction of displacement. Since the question states that the force is in the same direction as the displacement, theta = 0°, and cosine(0°) = 1.
Plugging in the values into the formula:
Work = 20N × 5m × Cosine(0°)
Since cosine(0°) = 1, the equation simplifies to:
Work = 20N × 5m × 1
Work = 100Nm
Therefore, the work done when a force of 20N moves a 5m load in its direction is 100Nm.