what volume (in litres) of 17.6M NaOH will be used to prepare 0.5M NaOH in 50,000ml?
you are diluting it 17.6/.5= 35.2 times
which means 1 part original, 34.2 parts water.
so total solution=50 liters, which means each "part" is 50/35.2=1.42 liters
so the volume of NaOH is 1.42 liters, and the volume of water to dilute it 1.42*34.2 = 48.56 liters
To find the volume of 17.6M NaOH needed to prepare 0.5M NaOH in 50,000ml, we can use the formula:
C1V1 = C2V2
Where:
- C1 is the initial concentration of NaOH (17.6M)
- V1 is the initial volume of NaOH we need to find
- C2 is the final concentration of NaOH (0.5M)
- V2 is the final volume of NaOH (50,000ml)
Rearranging the formula to solve for V1, we have:
V1 = (C2 * V2) / C1
Plugging in the values:
V1 = (0.5M * 50,000ml) / 17.6M
Now we can calculate the volume V1:
V1 = (0.5 * 50,000) / 17.6
= 1,428.57 ml
Since the question asks for the volume in liters, we need to convert the result from milliliters to liters:
V1 = 1,428.57 ml / 1000
= 1.43 liters
Therefore, the volume of 17.6M NaOH needed to prepare 0.5M NaOH in 50,000ml is approximately 1.43 liters.