the label of a bottle of NaOH bears the following of 46.7% and density of 1.57gml
calculate the molar concentration of it?
Is this a liquid solution? I will assume it is.
1000 mL x 1.57 g/mL x 0.467 x (1 mol/40 g) = ? mols/L = ?M
ya...it is supposed to be a liquid soluction
pls assist me with me with the solvings
M = mols NaOH/L of solution.
density of 1.57 g/mL x 1000 mL = 1570 grams = mass of solution
mass NaOH in that 1570 g = 1570 x 0.467 = ?
mols NaOH in the above = grams/molar mass = ? grams/40 = ?
That gives you mols/L which is molarity = M
To calculate the molar concentration of a solution, we need to know the amount of solute (in moles) dissolved in a given volume of solution (in liters).
Given:
Percentage concentration = 46.7%
Density of NaOH solution = 1.57 g/mL
First, we can calculate the mass of NaOH in one liter of solution:
Mass of NaOH = Density x Volume
= 1.57 g/mL x 1000 mL
= 1570 g
Next, we need to convert the mass of NaOH to moles using its molar mass. The molar mass of NaOH is calculated by adding the atomic masses of Na (22.99 g/mol), O (16.00 g/mol), and H (1.01 g/mol):
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol
= 40.00 g/mol
Moles of NaOH = Mass of NaOH / Molar mass of NaOH
= 1570 g / 40.00 g/mol
= 39.25 mol
Finally, we can calculate the molar concentration (or molarity) by dividing the number of moles of NaOH by the volume of the solution in liters:
Molar concentration (Molarity) = Moles of solute / Volume of solution (in liters)
= 39.25 mol / 1 L
= 39.25 M
Therefore, the molar concentration of the NaOH solution is 39.25 M.