a force of 40 n/w stretch a wire to 3.cm what force wil stretch it through 4.0cm an through
F = 4cm/3cm * 40N. =
A force of 40n stretches a wire through 5.0cm what force will stretch it through 8cm
To find the force required to stretch the wire to 4.0 cm, we can use Hooke's Law, which states that the force required to extend or compress a spring (or in this case, a wire) is directly proportional to the displacement.
Hooke's Law can be expressed as:
F = k * x
Where:
F is the force applied to the wire
k is the spring constant (a measure of the stiffness of the wire)
x is the displacement of the wire
In this case, we have the following information:
Force (F1) = 40 N
Displacement (x1) = 3.0 cm = 0.03 m
Displacement (x2) = 4.0 cm = 0.04 m
To find the spring constant (k), we need to rearrange Hooke's law:
k = F / x
Therefore, we can calculate the spring constant using the given force and displacement:
k = 40 N / 0.03 m
k ≈ 1333.33 N/m
Now, we can substitute the new displacement (x2) and the calculated spring constant (k) into Hooke's Law to find the force (F2) required to stretch the wire to 4.0 cm:
F2 = k * x2
F2 = 1333.33 N/m * 0.04 m
F2 ≈ 53.33 N
Therefore, the force required to stretch the wire through 4.0 cm is approximately 53.33 N.