A SPRING OF FORCE CONSTANT 1500Nm-1 IS ACTED UPON BY A CONSTANT FORCE OF 75N CALCULATE THE POTENTIAL ENERGY STORED IN TH
I suppose you want to find the Ep in the spring.
1) potential energy ==> Ep = (m)(g)(h) ==> for gravity.
potential energy ==> Esp = 1/2(k)(x^2)
2) spring force ==> Fx = (k)(x), where k is the spring force constant and x is the distance of spring.
First find x using equation 2.
x = Fx / K = 75/1500 = 15/300 = 1/20
Then plug in the x and K in the equation 1 for the spring.
Esp = 1/2(1500)(1/20)^2 = 1/400(1/2)(1500) = 1500/800 = 15/8J (answer)
P.S Check cause I did not use calculator.
To calculate the potential energy stored in a spring, you can use the formula:
Potential Energy = (1/2) * k * x^2
Where:
- k is the force constant of the spring (in this case, 1500 N/m).
- x is the displacement or compression of the spring from its equilibrium position.
In this case, since the constant force is given (75 N), we can find the displacement by dividing the force by the force constant:
x = F / k
x = 75 N / 1500 N/m
x = 0.05 m or 5 cm
Now that we have the displacement, we can calculate the potential energy:
Potential Energy = (1/2) * k * x^2
Potential Energy = (1/2) * 1500 N/m * (0.05 m)^2
Potential Energy = 1/2 * 1500 N/m * 0.0025 m^2
Potential Energy = 1/2 * 1500 N * 0.0025 m
Potential Energy = 1.875 J
Therefore, the potential energy stored in the spring is 1.875 Joules.