if 465cm Of Sulphur Oxide (So2) Can Diffuse Through Povous Portition In 30secs How LONg Will Equal Volume, 620cm^3 Of Hydrogen Sulphide (H2S) TaKe To Diffuse Through The Same Partition H 1, S 32, O 16

Pls I Need The Answer Quickly

I've responded to this problem a few days earlier where I brought up that I don't understand the equal volume statement. It isn't obvious to me that 465 cc is an equal volume of 620 cc. BYW, SO2 is sulfur(IV) oxide or sulfur dioxide.

To answer this question, we need to use the formula to calculate the time it takes for a gas to diffuse through a partition:

\( \text{Time} = \frac{{\text{Distance}}}{{\text{Rate of Diffusion}}} \)

First, we need to calculate the rate of diffusion of Sulphur Oxide (SO2).

The rate of diffusion depends on the molar mass of the gas. To calculate the molar mass of SO2, we add up the atomic masses of sulfur (S) and oxygen (O):

Molar mass of SO2 = (1 * S atomic mass) + (2 * O atomic mass)
= (1 * 32) + (2 * 16)
= 32 + 32
= 64 g/mol

Now, let's calculate the rate of diffusion of SO2:

Rate of diffusion of SO2 = \(\frac{{\text{Distance}}}{{\text{Time}}}\)

Given that 465 cm of SO2 diffuses through the partition in 30 seconds, we have:

Rate of diffusion of SO2 = \(\frac{{465 \text{ cm}}}{{30 \text{ s}}}\)

Next, we need to find the time it will take for Hydrogen Sulphide (H2S) with a volume of 620 cm^3 to diffuse through the same partition.

First, we need to calculate the molar mass of H2S. Similar to before, we add up the atomic masses of hydrogen (H) and sulfur (S):

Molar mass of H2S = (2 * H atomic mass) + (1 * S atomic mass)
= (2 * 1) + (1 * 32)
= 2 + 32
= 34 g/mol

Next, let's calculate the rate of diffusion of H2S:

Rate of diffusion of H2S = \(\frac{{\text{Distance}}}{{\text{Time}}}\)

Since we are trying to find the time it takes, we rearrange the equation:

Time = \(\frac{{\text{Distance}}}{{\text{Rate of diffusion}}} = \frac{{620 \text{ cm}^3}}{{\text{Rate of diffusion of H2S}}}\)

Finally, substitute the known values into the formula to calculate the time:

Time = \(\frac{{620 \text{ cm}^3}}{{\frac{{465 \text{ cm}}}{{30 \text{ s}}}}}\)

Now, you can solve the equation to find the time it takes for 620 cm^3 of H2S to diffuse through the same partition.