If 465cm^3 Of Sulphur Oxide (SO2) CAN diffuse Through Povous Portition In 30secs How Long Will Equal Volume
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To determine how long it would take for an equal volume of sulfur oxide (SO2) to diffuse through the same porous partition, we need to consider the following factors:
1. Molar Volume: The volume occupied by one mole of a gas under standard conditions is known as the molar volume. For an ideal gas at standard temperature and pressure (STP), the molar volume is approximately 22.4 liters.
2. Volume and Diffusion Rate: In your question, the given volume is 465 cm^3. However, in order to compare the diffusion rates, we need to convert this volume to liters. Since 1 liter is equivalent to 1000 cm^3, the given volume would be 465 cm^3 / 1000 cm^3/L = 0.465 liters.
3. Diffusion Rate: The rate of diffusion depends on various factors, including the size of the molecules, temperature, concentration, and nature of the medium. However, assuming all other factors are constant, we can use the given time of 30 seconds to determine the diffusion rate.
Now, to find the time it would take for an equal volume of SO2 to diffuse through the porous partition, we can set up the following proportion:
Volume1 / Time1 = Volume2 / Time2
Where Volume1 is the given volume (0.465 L in this case), Time1 is the given time (30 seconds), Volume2 is the unknown volume, and Time2 is the time we need to find.
Plugging in the values, we have:
0.465 L / 30 s = Volume2 / Time2
To find Time2, we can multiply both sides of the equation by Time2:
0.465 L * Time2 = Volume2 * 30 s
Now, to calculate Time2, we need to know the value of Volume2. The given question does not provide this information, so unfortunately, we cannot determine the exact time it would take for an equal volume to diffuse through the porous partition without this information.