two pool balls, each a mass of .2kg, collide as shown in the figure below. Before the collision, the black ball's velocity makes an angle of 30 degrees with the horizontal line. After the collision, the white ball's velocity makes an angle of 60 degrees with the vertical line. What is the black ball's speed after the collision?

what was the white ball's trajectory before the collision?

To find the black ball's speed after the collision, you need to use the principles of conservation of momentum and conservation of kinetic energy.

1. Start by breaking down the initial and final velocities of the black and white balls into their horizontal and vertical components:
- The initial velocity of the black ball (before the collision) makes an angle of 30 degrees with the horizontal line.
- The final velocity of the white ball (after the collision) makes an angle of 60 degrees with the vertical line.

2. Use trigonometry to calculate the horizontal and vertical components of the black ball's initial velocity:
- The horizontal velocity (Vbx) can be calculated using the formula: Vbx = Vb * cos(θ), where Vb is the magnitude of the initial velocity and θ is the angle it makes with the horizontal line.
- The vertical velocity (Vby) can be calculated using the formula: Vby = Vb * sin(θ).

3. Apply the principle of conservation of momentum:
- The total initial momentum of the system (before the collision) is equal to the total final momentum (after the collision).
- Since only the black and white balls are involved in the collision, the momentum equation can be written as: m1 * Vbx1 + m2 * Vbx2 = m1 * Vbx1' + m2 * Vbx2', where m1 and m2 are the masses of the two pool balls, Vbx1 and Vbx2 are their respective horizontal velocities before the collision, and Vbx1' and Vbx2' are their respective horizontal velocities after the collision.

4. Use the principle of conservation of kinetic energy:
- The total initial kinetic energy of the system (before the collision) is equal to the total final kinetic energy (after the collision).
- The kinetic energy equation can be written as: (1/2) * m1 * (Vbx1^2 + Vby1^2) + (1/2) * m2 * (Vbx2^2 + Vby2^2) = (1/2) * m1 * (Vbx1'^2 + Vby1'^2) + (1/2) * m2 * (Vbx2'^2 + Vby2'^2), where Vby1 and Vby2 are the respective vertical velocities before the collision, and Vby1' and Vby2' are the respective vertical velocities after the collision.

5. Solve the two equations from steps 3 and 4 simultaneously:
- Substitute the values of the masses, angles, and velocities into the equations.
- Since the black ball's speed after the collision (Vbx1') is the desired value, you can solve for it using algebraic manipulation and substitution.

By following these steps, you should be able to find the black ball's speed after the collision.