Precipitation Reactions

Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no reaction occurs, write NO REACTION. Express your answer as a chemical equation. Identify all of the phases in your answer.

cesium chloride and calcium sulfide

I went through the solubility rules and balanced the resulting equation and this is what I came up with:

2CsCl(aq) + CaS(aq) --> Cs_2S(s) + CaCl_2(aq)

I inputted this into the system and it said I am incorrect. Can someone please check my work and if it is indeed incorrect, then explain HOW to reach the correct solution (I don't need the answer).

Both products from this reaction are soluble in water creating no reaction.

Hmmm. Cesium is an alkali metal, isn't its' compounds soluble in water?

http://www.ausetute.com.au/solrules.html

To determine if a precipitation reaction occurs when cesium chloride and calcium sulfide are mixed, you need to consider the solubility of the resulting products.

First, you should write the dissociation equations for cesium chloride (CsCl) and calcium sulfide (CaS) based on their solubility rules:

CsCl(aq) → Cs+(aq) + Cl-(aq)
CaS(aq) → Ca2+(aq) + S2-(aq)

Next, you need to assess if any of the resulting ions will form an insoluble product. According to the solubility rules, most chloride salts are soluble and most sulfide salts are insoluble. However, there are some exceptions for sulfides.

Looking at the given reaction, Cs2S is formed. Cesium sulfide (Cs2S) is soluble, so it will not form an insoluble product. Therefore, there is no precipitation reaction in this case.

Hence, the correct answer would be to write "NO REACTION" as the molecular equation for the mixing of cesium chloride and calcium sulfide.

2cs+2S=2CsS