7. A bag contains 5 green marbles, 8 red marbles, 11 orange marbles, 7 brown marbles, and 12 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?
Can someone help me please???
since it's with replacement, there are 43 marbles for each draw
so, find P(red) * P(blue)
Of course! I can help you with that. In order to find the probability of choosing a red marble, replacing it, and then choosing a blue marble, we need to follow these steps:
1. Find the probability of choosing a red marble on the first draw.
2. Find the probability of choosing a blue marble on the second draw.
3. Multiply the probabilities from step 1 and step 2 together to find the final probability.
Step 1: Probability of choosing a red marble
In the bag, there are a total of 5 + 8 + 11 + 7 + 12 = 43 marbles.
So, the probability of choosing a red marble on the first draw is 8 out of 43, or 8/43.
Step 2: Probability of choosing a blue marble
Since we replaced the first marble we drew, the number of marbles in the bag remains the same. Therefore, there are still a total of 43 marbles.
The probability of choosing a blue marble on the second draw is 12 out of 43, or 12/43.
Step 3: Multiply the probabilities
To find the probability of choosing a red marble, then a blue marble, we multiply the probabilities from step 1 and step 2 together:
P(red, then blue) = (8/43) * (12/43)
Calculating this expression would give you the final answer for the probability of choosing a red marble, then a blue marble.